# Simple Dimensional Method for Hydraulic Problems

*by*R. B. Whittington,

**Serial Information**:

*Journal of the Hydraulics Division*, 1963, Vol. 89, Issue 5, Pg. 1-27

**Document Type:**Journal Paper

Discussion: (See full record)

Discussion: (See full record)

Discussion: (See full record)

Closure: (See full record)

**Abstract:**Every physical magnitude in a problem has a unique dynamic number. The physical magnitude is expressed dimensionally in terms of the measure-system components. This expression is divided by the physical magnitude itself. The quotient is the dynamic number. In hydraulic problems, the measure-system components are usually ρ (density), L (length), V (velocity), M (mass), L, T (time) dimensions are transformed into ρ, L, V dimensions through the identitites M ≡ ρL

^{3}and T ≡ L/V. Thus the dynamic number for viscosity is formed as follows: μ (viscosity) has the dimensions M/LT, which become ρ L V. Dividing by μ gives the dynamic number N

_{μ}= ρ L V/

_{μ}= R. Application of this simple system, to all of the physical magnitudes involved, yields a set of dynamic number N

_{0}, N

_{1}, N

_{2}, N

_{3}....... It is shown that any useful physical equation may be reduced to the form N

_{0}= f (N

_{1}, N

_{2}, N

_{3}.......), the nature of the function f being revealed only by physical analysis of the problem. When the appropriate dynamic numbers are substituted in this expression, the result is identical with that obtained by the more lengthy conventional methods of dimensional analysis such as the use of the π-theorem.

**Subject Headings:**Hydraulics | Viscosity | Density currents | Fluid velocity | Dynamic analysis |

**Services:**Buy this book/Buy this article

Return to search